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Learn more about the date and time functions DATETIME, DATE, SECONDS, SECONDS_BETWEEN, MINUTES, MINUTES_BETWEEN, HOURS, HOURS_BETWEEN, DAYS, DAYS_BETWEEN, WORKINGDAYS, WORKINGDAYS_BETWEEN, WEEKS, WEEKS_BETWEEN, MONTHS, MONTHS_BETWEEN, YEARS, YEARS_BETWEEN, BETWEEN, YEAR, MONTH, DAY, HOUR, MINUTE, SECOND, TODAY, NOW, WEEKNUMBER, DAYOFWEEK.
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Keep in mind that all dates are interpreted using the (proleptic) Gregorian calendar rules. The timezone used in these type of functions is the system default timezone of the server that hosts the Blueriq runtime where the function is executed. |
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The way in which date and time values are displayed in the user interface is determined by the date display formats, which can be configured per language code. |
Overview
Function | Description |
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DATETIME | Creates a dateTime value out of integers. |
DATE | Creates a date value out of integers. |
ADD PERIOD TO DATE | Calculates |
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DATETIME
You can use this function to create a dateTime value out of integers or numbers.
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Numbers will be rounded to integers. |
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There is also a conversion function DATETIME. |
Syntax
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DATETIME(year, month, day, hour, minute, second) |
- year - An integer value between and including 1 and 9999 that represents the year in the constructed date.
- month - An integer value between and including 1 and 12 that represents the month in the constructed date.
- day - An integer value between and including 1 and 31 that represents the day in the constructed date.
- hour - An integer value between and including 0 and 23 that represents the hours in the constructed time.
- minute - An integer value between and including 0 and 59 that represents the minutes in the constructed time.
- second - An integer value between and including 0 and 59 that represents the seconds in the constructed time.
Return type
- dateTime
Examples
DATETIME ( 2010 , 5 , 25 , 23 , 00 , 00 ) = 25-5-2010 23:00:00
DATETIME ( -2010 , 5 , 25 , 23 , 00 , 00 ) = UNKNOWN
DATETIME ( 2010 , 5 , 25 , 45 , 00 , 00 ) = UNKNOWN
DATE
You can use this function to create a date value out of integers or numbers.
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Numbers will be rounded to integers. |
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There is also a conversion function DATE. |
Syntax
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DATE(year, month, day) |
- year - An integer value between and including 1 and 9999 that represents the year in the constructed date.
- month - An integer value between and including 1 and 12 that represents the month in the constructed date.
- day - An integer value between and including 1 and 31 that represents the day in the constructed date.
Return type
- date
Examples
DATE ( 2010 , 5 , 25 ) = 25-5-2010
DATE ( -2010 , 5 , 25 ) = UNKNOWN
DATE ( 2010 , 2 , 29 ) results in an error
ADD PERIOD TO DATE
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a new date by adding a specified period to a specified date. |
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Syntax
Code Block |
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date + number period |
- date - The date that you want to add the specified period to.
- number - Specifies how may periods you want to add to the date.
- period - A keyword that specifies which time unit to add. Valid units are DAYS, WEEKS, MONTHS and YEARS.
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If you prefer a functional syntax, you can use the INCREMENT_period functions. For example: INCREMENT_DAYS( 01-01-2015, 1) = 02-01-2015 |
Return type
- date
Examples
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01-01-2015 + 1 DAYS = 02-01-2015
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01-01-2015 + 1 MONTHS = 01-02-2015
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01-01-2015 + 1 YEARS = 01-01-2015
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Calculates a new dateTime by adding a specified period to a specified |
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Syntax
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dateTime |
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Return type
...
Examples
01-01-2015 13:23:04 + 1 DAYS = 02-01-2015 13:23:04
01-01-2015 13:23:04 + 25 HOURS = 02-01-2015 14:23:04
01-01-2015 13:23:04 + 60 SECONDS = 01-01-2015 13:24:04
01-01-2015 13:23:04 + 1 MINUTES = 01-01-2015 13:24:04
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Calculates a new date by subtracting a specified period from a specified date. |
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Syntax
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- date - The date that you want to subtract the specified period from.
- number - Specifies how many periods you want to subtract from the date.
- period - A keyword that specifies which time unit to subtract. Valid units are DAYS, WEEKS, MONTHS and YEARS.
Return type
- date
Examples
01-01-2015 – 1 DAYS = 31-12-2014
01-01-2015 – 1 WEEKS = 25-12-2014
01-01-2015 – 1 MONTHS = 01-12-2014
01-01-2015 – 1 YEARS = 01-01-2014
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Calculates a new dateTime by subtracting a specified period from a specified dateTime. |
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Syntax
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- dateTime - The dateTime that you want to subtract the specified period from.
- number - Specifies how many periods you want to subtract from the dateTime.
- period - A keyword that specifies which time unit to subtract. Valid units are
DAYS, WEEKS, MONTHS, YEARS, HOURS, MINUTES
andSECONDS
.
Return type
- dateTime
Examples
01-01-2015 13:23:04 – 1 HOURS = 01-01-2015 12:23:04
01-01-2015 13:23:04 – 25 HOURS = 31-12-2014 12:23:04
01-01-2015 13:23:04 – 60 SECONDS = 01-01-2015 13:22:04
01-01-2015 13:23:04 – 1 MINUTES = 01-01-2015 13:22:04
PERIOD BETWEEN | Calculates |
PERIOD BETWEEN
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the period between two date or dateTime objects |
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Calculates the working days between two date or dateTime objects. | |
WORKINGDAYS_BETWEEN | Alternative notation for WORKINGDAYS BETWEEN. |
Returns |
Valid types for period are:
- SECONDS
- MINUTES
- HOURS
- DAYS
- WEEKS
- MONTHS
- YEARS
Syntax
Code Block |
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period BETWEEN date1 AND date2 |
- period - A keyword that specifies which time unit to return. Valid units are
DAYS
,WEEKS
,MONTHS
,YEARS
,HOURS
,MINUTES
andSECONDS
. - date1 - The date or dateTime value that represents the start date.
- date2 - The date or dateTime value that represents the end date.
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You can use the periods HOURS , MINUTES and SECONDS only if at least one of the dates is a dateTime object or expression. |
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The order in which the dates are placed is irrelevant. |
Return type
- integer
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If you prefer a functional syntax, you can call these methods as: |
Examples
DAYS BETWEEN DATE( 2010 , 1 , 1 ) AND DATE( 2010 , 2 , 1 ) = 31
DAYS_BETWEEN ( DATE ( 2010 , 1 , 1 ) , DATE ( 2010 , 2 , 1 ) ) = 31
DAYS BETWEEN DATE ( 2010 , 5 , 31 ) AND DATE ( 2010 , 6 , 1 ) = 1
DAYS BETWEEN DATE( 2010 , 5 , 31 ) AND DATETIME ( 2010 , 6 , 1 , 12 , 0 , 0 ) = 1
, since 1 day and 12 hours have elapsedDAYS BETWEEN DATETIME ( 2010 , 1 , 1 , 14 , 0 , 0 ) AND DATETIME ( 2010 , 1 , 2 , 13 , 0 , 0 ) = 0
, for only 23 hours have elapsed
YEARS BETWEEN DATE ( 2009 , 1 , 1 ) AND DATE ( 2010 , 1 , 1 ) = 1
YEARS BETWEEN DATE ( 2010 , 1 , 1 ) AND DATE ( 2020 , 1 , 1 ) = 10
YEARS BETWEEN DATE ( 2010 , 1 , 1 ) AND DATE ( 2011 , 5 , 1 ) = 1
YEARS BETWEEN DATETIME ( 2010 , 1 , 1 , 12 , 0 , 0 ) AND DATE ( 2011 , 1 , 1 ) = 0
, since 364 days and 12 hours have elapsed
YEAR
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the year of a date or dateTime value |
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Code Block |
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YEAR(date | dateTime) |
- date or dateTime - The date or dateTime value of which the year must be returned.
Return type
- integer
Examples
YEAR ( DATE ( 2015 , 01 , 01 ) ) = 2015
YEAR ( DATE ( 1978 , 04 , 11 ) ) = 1978
MONTH | Returns |
MONTH
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the month of a date or dateTime value |
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. |
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Syntax
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- date or dateTime - The date or dateTime value of which the month must be returned.
Return type
- integer
Examples
MONTH ( DATE ( 2015 , 01 , 01 ) ) = 1
MONTH ( DATE ( 1978 , 04 , 11 ) ) = 4
DAY | Returns |
DAY
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the day of a date or dateTime value |
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Syntax
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- date or dateTime - The date or dateTime value of which the day must be returned.
Return type
- integer
Examples
DAY ( DATE ( 2015 , 01 , 01 ) ) = 1
DAY ( DATE ( 1978 , 04 , 11 ) ) = 11
HOUR
HOUR
returns the hour of a dateTime value. The hour is returned as a number in the range 0 - 23.
Syntax
Code Block |
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HOUR(dateTime) |
- dateTime - The dateTime value of which the hour must be returned.
Return type
- integer
Examples
HOUR ( DATETIME ( 2015 , 5 , 25 , 00 , 00 , 00 ) ) = 0
HOUR ( DATETIME ( 2015 , 5 , 25 , 23 , 00 , 00 ) ) = 23
MINUTE
...
...
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Syntax
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MINUTE(dateTime) |
- dateTime - The dateTime value of which the minute must be returned.
Return type
- integer
Examples
MINUTE ( DATETIME ( 2015 , 5 , 25 , 00 , 00 , 00 ) ) = 0
MINUTE ( DATETIME ( 2015 , 5 , 25 , 23 , 45 , 00 ) ) = 45
SECOND
SECOND
returns the second of a dateTime value. The second is returned as a number in the range 0 - 59.
Syntax
Code Block |
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SECOND(dateTime) |
- dateTime - The dateTime value of which the second must be returned.
Return type
- integer
Examples
SECOND ( DATETIME ( 2015 , 5 , 25 , 00 , 00 , 00 ) ) = 0
SECOND ( DATETIME ( 2015 , 5 , 25 , 23 , 45 , 59 ) ) = 59
TODAY
This function returns the current date of the server. The date is given as base type date, formatted as dd-mm-yyyy.
Syntax
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TODAY |
Return type
- date
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The TODAY function returns a date stamp. It is only recalculated when the expression in which you use the TODAY function is reevaluated. This recalculation will not cause other expressions that use the TODAY function to be reevaluated. |
NOW
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the current date and time of the server. |
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Syntax
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NOW |
Return type
- dateTime
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The NOW function returns a date- and timestamp. It is only recalculated when the expression in which you use the NOW function is reevaluated. This recalculation will not cause other expressions that use the NOW function to be reevaluated. |
WEEKNUMBER
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WEEKNUMBER | Returns the week number within the year of a given date or dateTime value. |
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DAYOFWEEK | Returns the number of the day within the week of a given date or dateTime value. |
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For example, January 1, 2015 was a Thursday. Therefore week 1 of 2015 starts on December 29, 2014, and ends on January 4, 2015.
Syntax
Code Block |
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WEEKNUMBER ( date | dateTime ) |
- date or dateTime - The date or dateTime value of which the week number must be returned.
Return type
- integer
Examples
WEEKNUMBER ( DATE ( 2015 , 01 , 01 ) ) = 1
WEEKNUMBER ( DATETIME ( 2014 , 12 , 28 , 0 , 0 , 0 ) ) = 1
WEEKNUMBER ( DATE ( 2015 , 12 , 28 ) ) = 53
WEEKNUMBER ( DATE ( 2016 , 01 , 02 ) ) = 53
WEEKNUMBER ( DATETIME ( 2016 , 01 , 04 , 0 , 0 , 0 ) ) = 1
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DAYOFWEEK
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DAYOFWEEK
returns the number of the day within the week of a given date or dateTime value, as follows:
- Sunday = 1
- Monday = 2
- Tuesday = 3
- Wednesday = 4
- Thursday = 5
- Friday = 6
- Saturday = 7
Syntax
Code Block |
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DAYOFWEEK( date | dateTime ) |
- date or dateTime - The date or dateTime value of which the week number must be returned.
Return type
- integer
Examples
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DAYOFWEEK
( DATE ( 2015 , 01 , 01 ) ) = 5
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DAYOFWEEK ( DATETIME ( 2015 , 12 , 28 , 0 , 0 , 0 ) ) = 2
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DAYOFWEEK
( DATE ( 2016 , 01 , 02 ) ) = 7
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